4(2c-8)=1/7(49c+70)

Question

Solve equation, write a justification fro each step, and check solution

Answer 1

4(2c - 8) = 1/7 (49c+70)

49 and 70 are both divisible by 7.

We can factor the 4 back into the parentheses.

 

8c - 32 = 7c + 10

We need to isolate c. Move the 7c to the left side:

8c - 32 -7c = 7c + 10 - 7c

c - 32 = 10

 

Further isolate c by moving the 32 to the right side:

c - 32 +32 = 10 + 32

c = 42

 

Now to check the answer:

4 * (2 * 42 - 8) = 1/7 (49 *42 + 70)

4 * (84 - 8) = 1/7 (2058 + 70)

4 * 76 = 2128 / 7

304 = 304

Answer 2

4(2c-8)=(1/7)(49c+70)

use the distributive property on both sides to get...

8c-32=7c+10

can you finish from here ? (isolate the variable)