Arthur D. answered 10/17/14
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If all 11 letters were different then the answer would be 11!, or 11*10*9*...*3*2*1= ?
However, there are 2 E's and 2 L's.
The formula is (11!)/(2!)(2!)=(11*10*...*2*1)/(2*1)(2*1)=(11*10*9*8*7*6*5*3*2*1)= ? (the 4 in the numerator cancels with the 2*2 in the denominator) Multiply all the numbers to get the answer.