B,
You have to convert the data to standardized normal variables to use the probability data under the Normal distribution in your book.
Let x = a value from the unknown non-standardized Normal distribution
m = the mean for this distribution
s = the standard deviation for this distribution
z = the standardized version of x, where z has m=0 and s=1
z = (x - m) / s
(a) Find s given x = 24 and m = 30
So z = (24 - 30) / s and s = (24 -30) / z = -6 / z
Now we're told that 47.5% of area under the Normal distribution is between 24 & 30. We know that the area from the mean to the -1s point corresponds to 34.13% only so the 24 must be more than 1s away from the mean at 30. Looking up the standardized Normal table, 1.96s corresponds to 0.475 area. Thus z = -1.96 since we're to the left of the mean.
And s = -6 / -1.96 = 3.06
(b) I don't know what you mean by quartile? It could represent one-fourth of the area under the Normal distribution, or it could represent the -1.5 s point since that is one-fourth of 6 standard deviations which covers 99.79% of the area under the Normal distribution. In either case, you work with the z equation above.
If it's one-fourth the area, that first 25% point corresponds to z = -0.675
So, z = - 0.675 = (45 - m) / 3.5 and m = 0.675(3.5) + 45 = 47.36
If it's the second case, then (45 - m) / 3.5 = -1.5 and m = 1.5(3.5) + 45 = 50.25
Take your pick!