
Russ P. answered 10/15/14
Tutor
4.9
(135)
Patient MIT Grad For Math and Science Tutoring
Sam,
Let t = travel time, identical for both trains since they leave simultaneously.
d1 = distance traveled by the 55 mph train = 55t (distance = speed multiplied by time)
d2 = distance traveled by the 75 mph train = 75t
Since they are traveling towards each other, the total distance they must travel in time t to meet is the distance between the train stations, 364 miles.
Thus d1 + d2 = 364
55t + 75t = 364, so 130t = 364 and t = 364/130 = 2.8 hours
And they will meet at d1 = 55(2.8) = 154 miles from the slower train's station, or 210 miles from the other station.