
Brendan B. answered 10/20/14
Tutor
New to Wyzant
Physics Tutor -- High School & College
The capacity of the plant is an average power output, expressed in kW. Power is a rate, which describes how much energy is used over time. As an equation: P = E/t. In this case P=230 kW is equivalent to 230 kJ/s. In scientific notation: 2.3*105 J/s.
The energy stored in the basin is E=88 TJ, or terajoules. In scientific notation, this is 8.8*1013 J.
To solve for time (in seconds), divide the energy by the power:
t = E/P = 8.8*1013 J / (2.3*105 J/s) = 3.85*108 seconds.
This is somewhat unwieldy. A quick calculation shows that 60 s/min *60 min/hr *24 hr/ day *365 day/yr = 3.15*107 seconds in a year. So the plant can run for about 12.13 years!