
Nathan B. answered 10/08/14
Tutor
5
(20)
Elementary and Algebraic skilled
Let's start off with the number of matches. we have a total of 6: MN, MP, MT, NP, NT, & PT
P(atti) won all of hers, so P = 5 in all cases, and 15 total
N(ancy) = 10 total
M(anny) = 8 total
T(homas) = 8 total
NP + NM + NT = 10 (for opponents)
5 + a + b = 10
MP + MN + MT = 15 (for opponents)
5 + c + d = 15
Since there's five points max per round, Manny lost each of them:
5 + 5 + 5
TP + TN + TM = 14 (for opponents)
5 + e + f = 14
one short from 15, and we know from the previous hint that Manny lost, so
5 + 5 + 4 = 14
Here's the standings that we know so far, then:
MN (? 5), MP (? 5), MT (4 5), NP (? 5), NT(5 ?), & PT (5 ?)
P = 15, 15 accounted for
M = 8, 4 accounted for; 4 missing
N = 10, 10 accounted for
T = 8, 5 accounted for; 3 missing
With Nancy's 10 points fully accounted for, we can make NP (0 5) (since 10 + 0 = 10):
MN (? 5), MP (? 5), MT (4 5), NP (0 5), NT(5 ?), & PT (5 ?)
M has 4 points left, and T three points.
Let's take a closer look at Patti's matches now.
We know N has 0, and T > M (Thomas scoring more) , so we have:
0 + T + M = 2.
Since T is more, not equal, T must be 2, so 0 + 2+ 0 = 2
Now we can fill in the rest of Patti's matches:
MN (? 5), MP (0 5), MT (4 5), NP (0 5), NT(5 ?), & PT (5 2)
P = 15, 15 accounted for
M = 8, 4 accounted for; 4 missing
N = 10, 10 accounted for
T = 8, 7 accounted for; 1 missing
M = 8, 4 accounted for; 4 missing
N = 10, 10 accounted for
T = 8, 7 accounted for; 1 missing
Manny and Thomas only has one match left each unaccounted for, so we just put in what amount of points are left over, so now we have the final head-to-head scores:
MN (4 5)
MP (0 5)
MT (4 5)
NP (0 5)
NT (5 1)
PT (5 2)