Segodess R.
asked • 10/08/18Between z >1.36 and z <1.99
need help
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1 Expert Answer
Asif H. answered • 10/11/19
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Assuming that you are trying to calculate the probability : P(1.36 <z<1.99) and a normal distribution you should as below.
P(1,36 <z<1.99)
= P( z<1.99) - P(z<1,36)
= 0.97670 - 0.91309
= 0.06361
Barbara E.
How did you get from P(z<1.99)-P(z<1.36) to =0.97670 - .91309.... I'm stuck on how to get to the second step. How do I get here... z(<1.99) = 0.97670 how?
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10/13/19
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Philip P.
10/08/18