f(x) = x³ - 4x² - 3x + 4
To find the extrema, compute the first derivative, f'(x), set it to zero and solve for x:
f'(x) = 3x² - 8x - 3
0 = 3x² - 8x - 3
0 = (3x+1)(x-3)
x = -1/3 and 3
To determine whether the extreme points are maxima or minima, take the second derivative, f"(x). If it's positive at the extreme point, it's a minimum. If it's negative, it's a maximum. Test both extreme points.
To find inflection points, set the second derivative to zero and solve for x.
f(x) is increasing as it approaches a maximum or after a minimum. It is decreasing as it approaches a minimum or after a maximum. The intervals you need to check are: (-∞,-1/3), (-1/3,3), and (3.∞).