2.4(b + 22) = 4b

2.4b + 52.8 = 4b

1.6b = 52.8

b = 33

33 + 22 =

**55 mph**Angela C.

asked • 10/02/18Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2.4 h, and Car B traveled the distance in 4 h. Car A traveled 22 mph faster than Car B. How fast did Car A travel?

Follow
•
2

Add comment

More

Report

2.4(b + 22) = 4b

2.4b + 52.8 = 4b

1.6b = 52.8

b = 33

33 + 22 = **55 mph**

Ask a question for free

Get a free answer to a quick problem.

Most questions answered within 4 hours.

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.