J.R. S. answered • 09/25/18

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The decomposition of sodium azide (NaN

_{3}) is not as you have written it. It is2NaN

_{3 }=> 2Na(s) + 3N_{2}(g)a) 1.5 moles NaN

_{3}x 3mol N2/2 mol NaN3 x 28g/mol N2b) 5g N2 x 1 mol N2/28g x 2 mol NaN3/3 mol N2 x 65g/mol NaN3

c) Convert 5 cubic ft to liters using 1 cubic ft = 28.3 liters. Convert this to grams using density. 1.25 g/L x Liters = g

Convert to moles of N2 then find moles NaN3 using stoichiometry and then grams using molar mass.