the sum of 4 consecutive integers is 110.

Question

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Answer 1

You did not ask a question, but I assume you want to find what the 4 numbers are.

 

They are

 

n

n + 1

n + 2

n + 3

 

n + (n + 1) + (n + 2) + (n + 3) = 110

 

Solve for n.

 

4n + 6 = 110

 

n = (110 - 6)/4 = 26

 

Now get n + 1, n + 2, n + 3, and test the answer.