What is the equation of the line that passes through (–2, 4) and is perpendicular to 2x + 3y = –6?

Question

A.) y=-3/2x-2

B.) y=3/2x+7

C.) y=2/3x+8/3

D.) y=2/3x-4

Answer 1

What is the equation of the line that passes through (–2, 4) and is perpendicular to 2x + 3y = –6?

3y = -2x -6

y = (-2/3)(x) - 2

 

m = -2/3  (slope)

slope of perp line is opposite sign and inverse

m₁ = 3/2

y = (3/2)(x) + b

4 = (3/2)(-2) + b

4 = -3  + b

b = 7 (y intercept)

y = (3/2)(x) + 7