Inactive Tutor answered 01/12/21
Tutor
New to Wyzant
distance = speed times time
210 = (B+5)t
150=(B-5)t
t= 150/(B-5) = 210(B+5)
cross multiply
210B - 1050 = 150B + 750
60B = 1800
B = 30 mph in still water
Sekera J.
asked 09/20/18Inactive Tutor answered 01/12/21
distance = speed times time
210 = (B+5)t
150=(B-5)t
t= 150/(B-5) = 210(B+5)
cross multiply
210B - 1050 = 150B + 750
60B = 1800
B = 30 mph in still water
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