Find three consecutive odd integers such that the sum of the​ first, two times the​ second, and three times the third is 58

Question

PLEASE HELP It's urgent I know what the formula and how to work it out but every time I work this out I get a repeating decimal when I just need an integer.

Answer 1

1st odd integer is X

2nd odd integer is X+2

3rd off integer is X+4

 

X + 2(x+2) + 3(x+4) = 58

 

x + 2x + 4 + 3x + 12 = 58

6x + 16 = 58

6x = 42

x=7

 

7.9,11

 

7 + 2x9 + 3x11=

7+18+33 =

25 + 33 = 58

 

So yes, 7, 9 , and 11