According to data from a web aggregator collected about two social media​ sites,

Question

According to data from a web aggregator collected about two social media sites, one site for posting pictures of cats and another site for posting pictures of food acquired the same number of unique visitors in 2012. The site for posting pictures of cats took 64 months to acquire these visitors while the site for posting pictures of food took 33 months. The site for posting pictures of food had a rate of visitor growth of 590 comma 000 more a month, on average, than the site for posting pictures of cats.
Find the average rate of growth of the site for posting pictures of cats.

Answer 1

In 2012 both sites have x visitor

 

rate of cat picture site = x/ 64

 

rate of food picture site = x/33

 

x/64  +590,000 = x/33

 

LCM of denominator 33 and 64 is 2112

 

33x + 1,246,080,000= 64x

 

1,246,080,000 = 31x

 

40,196,129 ≈ x

 

rate of cat picture site = x/ 64 = 40,196,129/ 64 = 628064.5