h(×)=-2×^2-20×-50 what's the y and x intercept

Question

h(×)=-2×^2-20×-50

Answer 1

Allllllll along the y-axis, x = 0, right? All along the x-axis, y = 0.

 

2(0)² - 20(0) - 50 = 0 - 0 - 50 = -50, so the y-intercept is -50, or (0,-50).

 

2x²- 20x - 50 = 0

 

Let's divide that by the leading coefficient, since all the coefficients are also divisible by it.

 

x² - 10x - 25 = 0

(x - 5)(x - 5) = 0

 

In order for the two factors to multiply to be zero, one has to equal 0. In this case, they are both the same, x - 5, so we just need to solve once.

 

x - 5 = 0

x = 5

 

So, our x-intercept is 5, or (5,0).

 

Hope this helps!

 

Answer 2

h(x) = -2^{x^2} - 20^x - 50

 

    -2^{x^2}, -20^x, and -50 are negative for all x.  So, h(x) < 0 for all x.  

 

    So, there is no x-intercept.

 

y-intercept :  h(0) = -2⁰ - 20⁰ - 50 = -52     y-intercept (0, -52)