6(4x + 5)squared - (4x + 5) - 35

Question

6(4x + 5) squared - (4x + 5) - 35

Answer 1

Your teacher may have wanted you to make a substitution. Let u= 4x + 5. Replacing this in your expression you'd get

6u^2 - u - 35 which factors into

(2u - 5)(3u + 7) Now replace the u and get

[2(4x+5) - 5] [3(4x+5) +7] which simplifies to

(8x +5)(12x + 22)

2(8x+5)(6x+11)

Answer 2

6(4x+5)²-(4x+5)-35

6*35=2*3*5*7 and 2*7=14, 3*5=15, 15-14=1

[3(4x+5)+7][2(4x+5)-5]

if you want to go further...

[3(4x+5)+7][2(4x+5)-5]

(12x+15+7)(8x+10-5)

(12x+22)(8x+5)

2(6x+11)(8x+5)

Answer 3

6(4x+5)²-(4x+5)-35

 

6(4x+5)(4x+5)-(4x+5)-35

 

6(16x²+40x+25)-(4x+5)-35

 

96x²+240x+150-(4x+5)-35

 

96x²+240x+150-4x-5-35

 

96x²+236x+110

 

x=(-236±√(236²-4(96)(110))) / 2(96)

 

(-236±√(55696-42240)) / 192

 

(-236±√(13456)) / 192

 

(-236±116) / 192

 

(-236-116) / 192 = -352/192 = -11/6

 

(-236+116) / 192 = -120/192 = -5/8

 

x = -11/6 or -5/8