
Andy C. answered 08/30/18
Tutor
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Math/Physics Tutor
A+B+C+D+E = 5000
343A + 220B + 220C + 197D + 132E = 750000 <--- clears the decimal by multiplying everything by 1000
There are 5 unknowns with only 2 equations.
Hence, there are 3 free variables (3 degrees of freedom)
with which the solutions are derived numerically.
I'll choose C,D,E to be the free variables.
The first equation becomes A+B = k where k = 5000-c -d -e
The second equation becomes 343A + 220B = 750000 - 132e - 197d - 220c
Let t = 750000 - 132e - 197d - 220c
Solving the first equation for A, it is A = k - B
The second equation is 343(k-B) + 220B = t
343k - 343B + 220b = t
343k - 123b = t
343k - t = 123b
b = (343k - t)/123
So once C, D, E are selected, K and t can be calculated
Once k and t are calculated, b can be calculated.
Once b is calculated, then A can be calculated using the equation above in
bold that reads A = k - B
For example:
For C=250, D=500, E = 4000 The results are
B = 140.24 and A = 109.76
I have uploaded the spreadsheet FUNDS ALLOCATION
which allows you to specify values for C,D, and E and
will calculate A and B so that these conditions are met.
The filename is FUNDS ALLOCATION.xls