This problem is NOT clear.
As written it is: (21x/12) + sqrt(4x-4) the domain of which is x≥1.
If, in fact, the problem is 21x/[12 + sqrt(4x-4)], the domain is still x≥1.
Kristen S.
asked • 08/27/18what is the domain of 21x/12+sqrt(4x−4)
domain of 21x/12+√4x-4
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