Robert J. answered • 06/30/13

Certified High School AP Calculus and Physics Teacher

The domain of √(x+5) is x ≥ -5, and the domain of √(x-1) is x ≥ 1.

The domain of f(x)=3√(x+5)+7√(x-1) is the conjunction of x ≥ -5 and x ≥ 1.

Answer: x ≥ 1.

Veronica B.

asked • 06/30/13How ado you find the domain?

f(x)=3√(x+5)+7√(x-1)

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Robert J. answered • 06/30/13

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Certified High School AP Calculus and Physics Teacher

The domain of √(x+5) is x ≥ -5, and the domain of √(x-1) is x ≥ 1.

The domain of f(x)=3√(x+5)+7√(x-1) is the conjunction of x ≥ -5 and x ≥ 1.

Answer: x ≥ 1.

Steven W. answered • 07/01/13

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Math can be fun! Experienced tutor in Algebra, Calculus, Geometry

Robert gave a good answer for your specific question. In general when asked to find the domain of a function, we are interested in values of x where we get a real valued answer. That means the inside of a radical expression must be non negative. So they can be 0 or 4 but not -3 or -14 for example inside of the radical, since the solution to negative radicals are complex and this outside of our domain.

Therefore the expression sqrt(x+5), the x+5 must be positive or zero, so the least number x can be is -5. When we consider both expressions, both must follow this rule which is why we get that x must be greater than or equal to -1.

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