write the inequality and solve the equation

Question

admission to a carnival  is $8.00. You allow $5.00 for lunch and $3.00 for a snack. Each ride is $2.50. You have $40.00 to spend. how many rides can you go on? I know the answer is 12. But I need to know how to write the equation

Answer 1

Hello, Heather

 

I am assuming that 'you allow $5 for lunch and $ 3 for a snack' means that the admission ticket covers the lunch/snack. (Hey, how do I suppose to know, I don't go to carnivals ! :(

 

If this is the case then the inequality becomes

2.50 r + 8 <= 40

            -8       -8

         2.5r. <= 32            Dividing both sides by 2.5

               r<= 12.8

So, the maximum numbers of rides will be 12, you will still have 2 dollars left.  

 

D.Y. Taylor

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Answer 2

Your $8, $5 and $3 are all one time costs for the day. The rest of the money accumulates depending on how many rides you go on. That's were your variable comes in

 

Let r = the number of rides that you go on. That means 2.50r is how much money you spent on rides. Your total cost must be under $40. So,

 

8 + 5 + 3 + 2.50r <= 40

16 + 2.5r              <=40

          2.5r             <= 24

              r              <= 9.6

 

So you can go on 9 rides.

 

Let's work backwards and see if this is rightIf you go on 9 rides at 2.50 a piece, that's $22.50.

add8 for admission, that's 30.50.

add 5 for lunch, that's 35.50.

add 3 for snacks, that's 38.50

This leaves you with $1.50 from the $40 you brought. So I'm convinced that my answer is right.