what is negative ten plus one third "y" greater than or equal to two third "y"

what is negative ten plus one third "y" greater than or equal to two third "y"

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You would solve this one just like a regular algebraic equation. If it helps, change the problem (for now) into:

-10 + 1/3y = 2/3 y. (Be sure that when you put the inequality back in it faces the right way. More on that in a sec.)

So, we want to get all the y's on one side and all the rest of it on the other. To do this, let's subtract 1/3 y from both sides, giving us.

-10 = 1/3y. (The inequality symbol here would still be >= as we haven't changed much.)

Last step is to get rid of that 1/3, so let's multiply both sides by 3. We also need to put that inequality symbol back in. So:

-30 >= y.

Note: We can rewrite this so y is in front. If we do, we need to swap the direction the inequality points as well. (y <= -30) Same goes for if you multiply/divide this whole inequality by a negative number.