the sum of three consecutive even integers is at least 80 and at most 90. what is the largest possible combination of these three integers?

The sum of 3 consecutive even integers is at least 80 and at most

Call the first number X. The second will be X+2 (the next even number). The third is (X+2)+2=X+4. So the sum is X+X+2+X+4= 3X+6

So we now have 80 ≤ 3x+6 ≤ 90

80 -6≤ 3X+6-6≤ 90-6

74≤ 3X≤ 84

74/3≤ 3X/3≤ 84/3

24.666≤ X≤ 28

Since we know X is an even integer, the only options we have are 26 and 28.

We already said the X is the smallest number, and the next two are X+2 and X+4. Plugging in the 2 options for x, we have two possible solutions.

1) 26+28+30= 84

2) 28+30+32=90

## Comments

Since the question asks for the

largestcombination, the largest starting even integer in the range would do the job. The last step of comparing the possible combinations is illustrative, but not necessary.Keep it up, Gene!!! We need competent "feed back" and I like it. You are right here and were right about f(x) and f(x-1) (hope you remember comment about "x"). You push us to think better!! Here, in America, teacher (at least in public schools) is teaching the same subject level or the same grade years after years ... We forgot all connections before and after and don't see how is working our "work" in future ...