Write the equation of a linear function with this low before they go through the point (-8,-2)

Question

Please help! I am stuck on this problem and I have math as my first hour class first thing in the morning. 

Answer 1

To write the equation of a linear function that passes through the point (-8, -2), we need to determine the slope and the y-intercept. However, since the slope isn't provided, I'll assume you meant to find the equation given a specific slope. Let's use a general slope mm.

The equation of a linear function is given by:

y=mx+by=mx+b



Where mm is the slope and bb is the y-intercept.

Given the point (-8, -2), we can substitute these values into the equation to solve for bb:

−2=m(−8)+b−2=m(−8)+b

Rearranging to solve for bb:

b=−2+8mb=−2+8m

So, the equation of the linear function is:

y=mx+(−2+8m)y=mx+(−2+8m)

If you provide a specific slope, I can give you the exact equation. For example, if the slope mm is 2:

b=−2+8(2)=−2+16=14b=−2+8(2)=−2+16=14

Thus, the equation would be:

y=2x+14y=2x+14