Lauren H. answered 08/23/18
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Experienced High School Chemistry Teacher
50 wk/yr x 300 mi/wk x 1 gal/25 mi x 20 lb/ gal = 12,000 lbs/year of CO2
However, since a gallon only weighs 8.3lb, you can't possibly produce 20 lbs of CO2/ gallon of gas. This breaks the law of conservation of mass, so, you've either copied the problem incorrectly or it's a poorly written problem...
Lauren H.
2C8H18 + 25O2 → 16CO2 + 18H2O
0.453592 kg octane/lb x 8.3 lb x 1000g/kg x 1 mole/ 114.23 g x 25 mole O2/2 mole octane x 32 g O2/ 1 mole O2 x 1 kg O2/1000 g O2 x 1 lb/.453592 kg =
Well, if I didn't screw this up, you'd use 29.1 lbs of O2...
So, I guess a gallon of gas could produce that much CO2... That is quite sobering...
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08/23/18
J.R. S.
08/23/18