what are the dimensions of a rectangle if the length is one more than twice the width and the perimeter of the rectangle is 38?

Question

it is about the 5D prosses

Answer 1

Let w = the width

Let 2w + 1 = the length

P = 2l + 2w

38 = 2(2w + 1) + 2w

38 = 4w + 2 + 2w

36 = 6w

6 = w

2w + 1 = 2(6) + 1 = 13