Jessica O.

asked • 08/22/18

(9x)/(4-(sqrt(6x-38)))

find the domain
 

2 Answers By Expert Tutors

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Doug C. answered • 08/22/18

Math Tutor with Reputation to make difficult concepts understandable

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Rebecca R. answered • 08/22/18

Experienced Elementary School Math and Algebra 1 Tutor

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Doug C.

6x-38 must be greater than zero, so not taking the square root of a negative number. 
 
Check out the graph of this function:
 
https://www.desmos.com/calculator/qgvcaurvrk
 
 
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08/22/18

74caf8a0 b265 479d 997b 9d49d1c3fdd1

Rebecca R.

tutor
Doug is correct. You cannot have a square root of a negative number . So, 6x - 38 needs to be > 0
 
6x - 38 > 0
6x > 38
x > 19/3 
Therefore the correct answer should be  the set of real numbers such that  x > 19/3  , x≠9
 
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08/22/18

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