Doug C. answered • 08/22/18

Math Tutor with Reputation to make difficult concepts understandable

Jessica O.

asked • 08/22/18find the domain

More

Doug C. answered • 08/22/18

Math Tutor with Reputation to make difficult concepts understandable

6x - 38 must be greater than 0 too, because otherwise taking the square root of a negative number.

Check out this graph:

https://www.desmos.com/calculator/qgvcaurvrk

Rebecca R. answered • 08/22/18

Experienced Elementary School Math and Algebra 1 Tutor

Hi, Jessica.

Okay, so you need to find the domain. You need to show that there cannot be an answer with a denominator of 0.

So, let's evaluate the denominator:

4 - √(6x - 38)

This cannot be equal to 0 , so let's solve for zero and find where the solution does not exist.

4 - √(6x - 38) = 0

4 = √(6x - 38)

16 = 6x - 38

6x = 54

x = 9

So, at x = 9, there is not solution, therefore the domain is:

x = the set of all real numbers **except x = 9**

Rebecca R.

tutor

Doug is correct. You cannot have a square root of a negative number . So, 6x - 38 needs to be > 0

6x - 38 > 0

6x > 38

x > 19/3

Therefore the correct answer should be the set of real numbers such that **x > 19/3 , x≠9**

Report

08/22/18

Ask a question for free

Get a free answer to a quick problem.

Most questions answered within 4 hours.

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.

Doug C.

08/22/18