If 5.21 g of silver nitrate react with sodium phosphate what mass of silver phosphate is produced.

Question

formula: 3AgNO3 + Na3PO4 → 3NaNO3 + Ag3PO4

Answer 1

Hello Sarah

 

We will need to use stoichiometry to convert mass of AgNO₃ to mass of Ag₃PO₄.  The process is as follows:

 

g AgNO₃ → mol AgNO₃ → mol Ag₃PO₄ → g Ag₃PO₄

 

The molar masses of AgNO₃ and Ag₃PO₄ are 170 g/mol and 419 g/mol, respectively.  Also from the balanced chemical reaction, 3 moles of AgNO₃ reacts to form 1 mole of Ag₃PO₄.

 

5.21 g AgNO₃ x (1 mol AgNO₃ / 170 g AgNO₃) x (1 mol Ag₃PO₄ / 3 mol AgNO₃) x (419 g Ag₃PO₄ / 1 mol Ag₃PO₄) = 4.28 g Ag₃PO₄