write the equation of the line containing the point (3,56) and perpendicular to 3x-2y=8

Question

can you include the steps??

Answer 1

Since the line is perpendicular, its slope must be the negative reciprocal of the slope of the given line.

 

Slope of given line:

 

m₁ = -3/-2 = 3/2

 

Slope of perpendicular line:

 

m₂ = -1/m₁ = -1/(3/2) = -2/3

 

In point-slope form, the equation of the perpendicular line is

 

y - y₂ = m₂(x - x₂)

 

x₂ = 3

y₂ = 56

 

Plug in the numbers.