SURENDRA K. answered • 09/23/14

An experienced,patient & hardworking tutor

For x= 0 it is 0/0 form

So, we can apply L' Hopital's rule.

5sin(5x)/(-6sin(6x))

=(-5/6)*(sin(5x)/5x)*(6x/sin(6x))*(5x/6x)

On taking limits now

= (-5/6)*(5/6)

=-25/36

We are using the standard result here----

limit. sin(x)/x. as x tends to 0

=1

So, limit sin(5x)/5x. as x tends to 0

=1

And,

Limit sin(6x)/6x. as x tends to 0

=1

SURENDRA K.

If you want to learn limits fully well,

You have to learn L'Hopital's rule.

Report

09/24/14

Sarah J.

look, my teacher hasnt taught this to us yet and this was a question on the test. i want to learn how to do this without the use of l'hopitals rule or derivatives sop could you please just tell me how?

Report

09/24/14

Sarah J.

09/23/14