Ishwar S. answered 08/02/18
Tutor
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University Professor - General and Organic Chemistry
Hello Derick
Ethane cannot react with chlorine to form chloromethane as ethane is a 2-carbon alkane and methane is a 1-carbon alkane. Therefore, there is some error in the question.
I will assume the starting alkane is METHANE, the product is chloromethane, and will answer the questions for you.
The overall reaction is:
CH4 (g) + Cl2 (g) → CH3Cl (g) + HCl (g)
This reaction is called free-radical chlorination and the mechanism involves 3 main steps. The first step is called the chain initiating step where the chlorine molecule splits into 2 chlorine radicals. The splitting of the chlorine molecule into the 2 radicals requires UV light as this supplies the energy needed to break the covalent bond between the 2 chlorine atoms in the molecule.
A) Chain Initiating Step
Cl2 + UV light → 2Cl•
B) Chain Propagating Step
Cl• + CH4 → CH3• + HCl
In the above reaction, the chlorine radical reacts with the first methane molecule to form a methyl radical and HCl.
CH3• + Cl2 → CH3-Cl + Cl•
The methyl radical then reacts with a chlorine molecule to form one molecule of chloromethane and in the process generates another chlorine radical. This Cl radical then reacts with another molecule of methane and the above 2 steps continue until either all the methane and/or chlorine molecules have reacted.
C) Chain Terminating Step
This can involve 3 separate reactions where any free radicals present in the reaction mixture can combine to end (or terminate) the reaction.
a) CH3• + Cl• → CH3-Cl
b) Cl• + Cl• → Cl2
c) CH3• + CH3• → CH3-CH3
The combination of the two CH3• radicals produces the alkane, ethane (C2H6), which is the "other organic product other than chloromethane formed in the terminating step." (answer to part 3 of your questions above).
Hope the above was helpful!