interior angles

Question

Determine the number of sides in a polygon if the sum of the interior angles is 5400^o

Answer 1

The formula for the sum of the interior angles of a polygon is:

 

S = (n-2)·180°

 

where S is the sum and n is the number of sides.  You are given S = 5400°:

 

S = (n-2)·180°

5400° = (n-2)·180°

 

Solve for n.

Answer 2

sum of angles in a polygon with n sides = 180(n-2)

 

180(n-2) = 5400

 

n-2 = 30

 

n = 32

 

it has 32 sides