Damazo T. answered 09/21/14
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Math Tutoring by 15 year veteran math teacher/Real cheap! :)
Hey, Dalton
This is one of my favors, the Distributive Property. This problem is easy but if you are not careful you can mess it up. I am going to do it an organized fashion. Ready,
(x) (2x^2) = 2x^3 add the exponents of x: 1+2 =3. Remember if you don't see an exponent, the exponent is 1.
(x) (3x) = 3x^2 add the exponents of x: 1+1 =2
(x) (5) = 5x
(y)(2x^2) = 2x^2y don't add the exponents since they are different variables
(y) (3x) = 3xy
(y) (5) = 5y
Well, we are done using the Distributive Property. Now, we need to check if we have like terms. Nope. They are all different.
So, the final answer will be 2x^3+ 3x^2+ 2x^2y+3xy+5x+5y
Good luck
D.Y. Taylor
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