stats questions

Question

A random sample of 159 full-grown lobsters had a mean weight of 18 ounces;
the standard deviation of weights of all lobsters is thought to be σ = 2.8 ounces.

Use this data to construct a 98 percent confidence interval for the population mean μ of
weights of all such lobsters. .


16.9 < μ < 18.0


18.1 < μ < 20


17.48 < μ < 19.52


17.48 < μ < 18.517

Answer 1

 

 

(17.48 , 18.52)

 

98% confidence ---> constant is k=2.33

margin of error k*std dev / sqrt(n)

 

2.33 * 2.8/sqrt(159) =  0.5173868545225 is the margin of error

 

adds and subtracts this from 18 to get the confidence interval as shown above