Suppose z varies directly with x and inversely with the square of y . If z = 6 when x=2 and y=4 , what is z when x = 10 and y=6 ?

Question

Not sure how to work out both to find z=

Answer 1

z = kx/y²

6 = k(2)/4²

6 = 2k/16

6 = k/8

48 = k

 

z = 48(10)/6²

z = 480/36

z = 13 1/3