
Rich G. answered 06/15/18
Tutor
5.0
(142)
Adjunct instructor, IXL video contributor
You have to do exactly what it says, substitute the values for E and A
A = 12x2+12Lx
L = 1/3 (E-24x)
If E = 98
L = 1/3 (98-24x)
L = 98/3 - 8x
A = 12x2 + 12Lx
If A = 448
448 = 12x2+12Lx
Factor out 12x
448 = 12x(x+L)
Since L = 98/3 - 8x
448 = 12x[x + (98/3 - 8x)]
448 = 12x[98/3-7x]
448 = 392x - 84x2
84x2-392x+448 = 0
Factor out 28
3x2-14x+16 = 0