Physics Question about velocity, speed, and acceleration

Question

if something goes down a ramp with a velocity of 2.5 m/s then accelerates at 0.35 m/s/s for 15 seconds, what is the speed at the bottom of the ramp?

Answer 1

I assume you mean that the object has an initial speed of 2.5 m/s as it begins accelerating down a ramp at 0.35 m/s/s.  Since the acceleration is constant, the instantaneous velocity at time t is:

 

v(t) = v₀ + at

• v(t) velocity at time t seconds after the acceleration starts
• v₀ = initial velocity = 2.5 m/s
• a = acceleration = 0.35 m/s²
• t = time (in seconds) = 15 seconds

 

Plug in the numbers and compute the answer.