You have 5.50L of oxygen gas at a temperature of 21.0°C. What is the volume of the gas at 35°C?

Question

This is a chemistry question i need help with

Answer 1

At constant pressure,

 

V₁/T₁ = V₂/T₂ ⇒

 

V₂ = (T₂/T₁)V₁

 

Work with absolute temperature.

 

V₂ = [(35 + 273)/(21 + 273)] (5.50 L) = 5.76 L

Answer 2

This problem is based on Charles' Law (a special case of the ideal gas law). It states that the volume of a fixed mass of a gas is directly proportional to the temperature. This law applies to ideal gases held at a constant pressure, where only the volume and temperature are allowed to change.

According to this law, V/T =K (constant). Or V1/T1=V2/T2 V1=5.50L, T1= 273+21=294, V2=?, T2=273+35=308 5.50/294=V2/308 (cross multiply) V2=(5.50x308)/294 = 5.76L