the function h (t) =-2t^2 + 8t +1 represents the height of the ball t seconds after it was thrown. what is the maximum height the ball reaches

Question

h(t) = -2t + 8t + 1. the maximum height for this equation 

Answer 1

First we have to find the time of the vertex.

 

t = -b/2a

t = -8/(2(-2))

t = -8/-4

t = 2

 

h(2) = -2(2²) + 8(2) + 1

h(2) = -8 + 16 + 1

h(2) = 9