How much each boy has

Question

Two boys have 33 dollars in cash between them. One gives 6 dollars to the other and finds he now has twice as much money as his friend. Form an equation by letting x dollars be the amount one boy had at the start. Hence find how much each boy has now.

Answer 1

before                after

First boy:             X                     X-6

Second boy:    33 - X                   33 - X + 6

 

Confused at all? The two boys totaled 33 bucks, which means one has the leftovers from 33. The rest should be clear enough: one lost 6 and the other gained it. Now we need an equation:

 

 

X - 6 = 2(33 - X +6) X - 6 = 66 - 2X + 12 X - 6 = 78 - 2X +2X +2X 3X - 6 = 78 +6 +6 3X = 84 /3 /3 X = 28 So the first boy had 28 before, and his buddy had 33 - 28 = 5 Afterward, the first boy had 28 - 6 = 22 and his friend had 5 + 6 = 11 Sorry it's so tough to read! I accidentally sent it before I was done, and when you edit, it's much tougher to create line breaks and such