Arturo O. answered • 05/19/18
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t = number of months
P0 = initial population
At the end of each month, the population is 1.08 times what is was at the start of the month.
P(t) = P0 (1.08)t = 74 (1.08)t
t = 1 year = 12 months
P(12) = 74 (1.08)12 = ?
Arturo O.
Why was this answer down-voted? The solution is correct. The down-vote is frivolous and unjustified.
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05/19/18
First L.
No it was not I tried it and didn’t get the right answer but the equation I got was right I down-voted your answer because it was wrong??
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05/19/18
First L.
Your solution was frivolous and unjustified
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05/19/18
Arturo O.
My solution is correct. This problem represents exponential growth, since at the end of each month, the population is 8% higher than at the start of the month, which is an increase by a factor of 1.08 each month. That means that after t months, the population has increased by a factor of (1.04)t, above the initial population of 74. So after t months,
P(t) = P0 (1.08)t = 74 (1.08)t
Then after 12 months,
P(12) = 74 (1.08)12,
as in my solution. Read up on exponential growth and see that my solution and explanation are correct. The down-vote is frivolous and unjustified.
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05/20/18
Arturo O.
I meant to say 1.08 instead of 1.04 in my comment above.
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05/20/18
First L.
Okay but I was asking for geometric series it isn’t increasing by 1.08 it is just .08 and it is the sum and I got the right answer an yours was wrong sorry but get over it thank you for trying to help :)
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05/20/18
Arturo O.
My answer is not wrong. The problem statement says it increases by 8% each month, which means it increases by a factor of 1.08 each month.
x + (8% of x) = 1.08x
That is exponential growth, and it is correctly represented by the equation
P(t) = P0 (1.08)t
As I said before, read up on exponential growth and see that it applies to this problem.
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05/20/18
First L.
05/19/18