This problems is a bit tricky because the resulting solid should be viewed as being into two parts joined together.
The first part corresponds to 0 ≤ x < 1 and the second to 1 ≤ x ≤ 9
The volume of the first part can be computed using the disk method : The integration is over x with limits 0 and 1
the integrand is π x leading to V1 = π/ 2
The second can also be computed using the disk method. The integration is over x with limits 1 and 9
the integrand is π x2 leading to V2 = π/3 (93 -1 )
The total volume is V1 + V2 = π [ 1/2 + 81 - 1/3)