How do you balance this equation : CuFeS2+O2+SiO2=Cu2S+FeSiO3+SO2+ Cu2O

Question

I'm not able to balance the Cu and O's, would someone please be able to explain to me how you balance this equation? Any help would be much appreciated. Thank you

Answer 1

4CuFeS₂ + 9.5O₂ + 4SiO₂ ==> Cu₂S + 4FeSiO₃ +  7SO₂ + Cu₂O

.........Left...........Right

Cu......4................4...

Fe......4................4...

S.......8................8...

O......27..............27...

Si.....4................4...

 

To put it in a more conventional form, multiply all coefficients by 2 to get whole number of oxygens:

8CuFeS₂ + 19O₂ + 8SiO₂ ==> Cu₂S + 8FeSiO₃ + 14SO₂ + Cu₂O