The Quadratic Formula

Question

An object is-thrown upward at a speed of 132 feet per second by a machine from a height of 18 feet off the ground. The height h of the object after t seconds can be found using the equation h=−16t^2+132t+18.
When will the height be 208 feet? _____seconds.
When will the object reach the ground? ____ Seconds.

Answer 1

208 = -16t² + 132t + 18

-16t² + 132t - 190 = 0

-8t² + 66t - 95 = 0

 

x = (-b ± √(b² - 4ac))/2a

 

x = -66 ±√((-66)² - 4(-8)(-95))/(2-8))

 

The rest is on you.