It isn't clear to me what the stated interval has to do with the problem.
f(t) is continuous on [-4,6] and the graph is a straight line.
F(x) = ∫2x (2t + 4)dt = (t2 + 4t |2x = x2+ 4x - (4 + 8) = x2 + 4x - 12
If I missed the point of the question, please send me a message.