rectangle has an area of 56 and a perimeter of 60, what is the length and width?

Question

Rectangle has an area of 56 and a perimeter of 60, what is the length and width?

Answer 1

A=lw

56=lw

P=2l+2w

60=2l+2w

30=l+w

30-w=l

56=(30-w)w

56=30w-w²

w²-30w+56=0

56=2*2*2*7=(2)*(2*2*7)=2*28

(w-2)(w-28)=0

w-2=0

w=2

w-28=0

w=28

l=28 units and w=2 units

all this amounts to is: 60/2=30, now find two addends that add up to 30 and multiply to make 56 (2 and 28)