
Arturo O. answered 04/24/18
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Total charge must be conserved.
q = (-4 + 4.5) x 10-6 C = 0.5 x 10-6 C
Then the finger and the electroscope must both have 0.25 x 10-6 C. That means the finger gained -4.25 x 10-6 C of negative charge. Divide that by the electron charge, -1.6 x 10-19 C, and that gives the number of electrons transferred between the two.