Carol H. answered 04/21/18
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Let r = the speed of the motorboat
Let c = the speed of the current
d = rt
15 = (r + c)3
10 = (r - c)5
15 = 3r + 3c Multiply both sides of this equation by 5.
10 = 5r - 5c Multiply both sides of this equation by 3.
75 = 15r + 15c
30 = 15r - 15c Add these two equations together.
105 = 30r
3.5 mph = r
15 = 3(3.5) + 3c
15 = 10.5 + 3c
4.5 = 3c
1.5 mph = c