temperature of this ideal gas

Question

0.3x10^4 liters of a ideal gas under a pressure of 0.0006x10^6 atmospheres had a temperature of 3500x10^7K. after the volume was doubled and the pressure increased to 0.03x10^5 atmospheres, what was the temperature of this ideal gas?

Answer 1

 

Look up R, the universal gas constant, in your textbook.  Get n, the number of moles, from

 

n = P₁V₁ / (RT₁)

 

You were given

 

P₁ = 0.0006 x 10⁶ atm

V₁ = 0.3 x 10⁴ L

T₁ = 3500 x 10⁷ K

 

Plug in the numbers in compatible units and get n.  then

 

T₂ = P₂V₂ / (nR)

 

P₂ = 0.03 x 10⁵ atm

V₂ = 2V₁. 

 

Just plug in the numbers in compatible units and get T₂.