The sum of 3 integers is 47 . The second integers is 6 times the first integer . The third integer is 7 more then the first what are the integers?

Question

Algebra driving me crazy

Answer 1

Let m, n, l are three integers. Then

m+n+l=47 (1)

n=6m        (2)

l=m+7       (3)

Plug in (2( and (3) into (1):

m+6m+m+7=47

8m=40,

m=5

n=30

l=12

 

So the three integers are 5, 12 and 30